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Cc Algebra Chapter 3 Answers

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iii.i Functions and Office Annotation

1.

  1. yes
  2. yes (Note: If ii players had been tied for, say, 4th place, then the name would not take been a role of rank.)

6.

y = f ( x ) = x 3 2 y = f ( x ) = x 3 2

9.

  1. aye, because each bank account has a unmarried balance at any given time;
  2. no, considering several bank account numbers may accept the aforementioned balance;
  3. no, because the aforementioned output may correspond to more than one input.

10.

  1. Yes, letter grade is a role of per centum class;
  2. No, information technology is not one-to-one. There are 100 different percent numbers we could get but simply about v possible letter grades, so there cannot exist but one percent number that corresponds to each letter form.

12.

No, because information technology does not pass the horizontal line test.

iii.2 Domain and Range

i.

{ 5 , 0 , 5 , x , 15 } { five , 0 , 5 , 10 , fifteen }

three.

( , one 2 ) ( 1 2 , ) ( , 1 2 ) ( 1 2 , )

4.

[ 5 two , ) [ 5 ii , )

5.

  1. values that are less than or equal to –2, or values that are greater than or equal to –one and less than 3
  2. { 10 | x 2 or one x < 3 } { x | 10 2 or ane ten < 3 }
  3. ( , two ] [ one , 3 ) ( , 2 ] [ one , 3 )

6.

domain =[1950,2002] range = [47,000,000,89,000,000]

7.

domain: ( , 2 ] ; ( , 2 ] ; range: ( , 0 ] ( , 0 ]

iii.3 Rates of Modify and Behavior of Graphs

ane.

$ 2.84 $ 2.31 five years = $ 0.53 five years = $ 0.106 $ two.84 $ 2.31 5 years = $ 0.53 five years = $ 0.106 per twelvemonth.

4.

The local maximum appears to occur at ( 1 , 28 ) , ( 1 , 28 ) , and the local minimum occurs at ( 5 , fourscore ) . ( five , 80 ) . The function is increasing on ( , 1 ) ( 5 , ) ( , ane ) ( 5 , ) and decreasing on ( 1 , 5 ) . ( i , 5 ) .

Graph of a polynomial with a local maximum at (-1, 28) and local minimum at (5, -80).

3.iv Limerick of Functions

1.

( f one thousand ) ( x ) = f ( ten ) g ( 10 ) = ( x 1 ) ( x 2 1 ) = x 3 ten 2 x + 1 ( f g ) ( ten ) = f ( x ) yard ( x ) = ( x ane ) ( x ii i ) = x ten 2 ( f yard ) ( x ) = f ( 10 ) thousand ( x ) = ( 10 1 ) ( x 2 i ) = x 3 x ii ten + 1 ( f g ) ( x ) = f ( ten ) g ( x ) = ( x 1 ) ( x two 1 ) = x 10 two

No, the functions are not the same.

2.

A gravitational force is however a force, and then a ( G ( r ) ) a ( G ( r ) ) makes sense as the acceleration of a planet at a distance r from the Sun (due to gravity), but G ( a ( F ) ) Thou ( a ( F ) ) does non make sense.

iii.

f ( chiliad ( 1 ) ) = f ( 3 ) = 3 f ( chiliad ( 1 ) ) = f ( 3 ) = iii and m ( f ( four ) ) = g ( ane ) = 3 g ( f ( 4 ) ) = thou ( 1 ) = 3

4.

k ( f ( 2 ) ) = g ( 5 ) = three g ( f ( 2 ) ) = yard ( five ) = 3

half-dozen.

[ 4 , 0 ) ( 0 , ) [ 4 , 0 ) ( 0 , )

7.

Possible answer:

k ( x ) = 4 + x 2 h ( x ) = 4 3 x f = h one thousand g ( x ) = 4 + x 2 h ( 10 ) = 4 three 10 f = h g

3.five Transformation of Functions

1.

b ( t ) = h ( t ) + x = 4.9 t 2 + thirty t + 10 b ( t ) = h ( t ) + x = 4.ix t 2 + 30 t + ten

two.

The graphs of f ( x ) f ( x ) and grand ( ten ) g ( x ) are shown below. The transformation is a horizontal shift. The function is shifted to the left past two units.

Graph of a square root function and a horizontally shift square foot function.

iv.

one thousand ( ten ) = 1 x - i + one yard ( x ) = 1 ten - 1 + ane

6.

  1. g ( x ) = f ( x ) 1000 ( 10 ) = f ( x )

    x x -two 0 two four
    g ( 10 ) yard ( x ) 5 five 10 10 15 15 20 20
  2. h ( 10 ) = f ( x ) h ( x ) = f ( 10 )

    x x -2 0 2 4
    h ( 10 ) h ( x ) xv 10 five unknown

vii.

Graph of x^2 and its reflections.

Detect: one thousand ( x ) = f ( x ) thou ( 10 ) = f ( x ) looks the same as f ( 10 ) f ( ten ) .

9.

x 10 2 four half-dozen 8
g ( x ) thousand ( x ) ix 12 15 0

11.

thou ( x ) = f ( i 3 x ) thou ( x ) = f ( ane three x ) so using the foursquare root part we get thousand ( x ) = ane 3 x chiliad ( x ) = 1 three x

iii.6 Absolute Value Functions

1.

using the variable p p for passing, | p 80 | 20 | p 80 | 20

two.

f ( x ) = | ten + ii | + 3 f ( x ) = | x + two | + iii

3.7 Inverse Functions

four.

The domain of role f 1 f 1 is ( , ii ) ( , 2 ) and the range of function f 1 f 1 is ( 1 , ) . ( ane , ) .

five.

  1. f ( 60 ) = 50. f ( 60 ) = fifty. In threescore minutes, fifty miles are traveled.
  2. f 1 ( 60 ) = 70. f 1 ( 60 ) = 70. To travel 60 miles, it will take seventy minutes.

8.

f ane ( x ) = ( ii ten ) 2 ; domain of f : [ 0 , ) ; domain of f 1 : ( , 2 ] f 1 ( x ) = ( 2 x ) 2 ; domain of f : [ 0 , ) ; domain of f i : ( , 2 ]

three.1 Department Exercises

1.

A relation is a set of ordered pairs. A part is a special kind of relation in which no two ordered pairs have the same first coordinate.

3.

When a vertical line intersects the graph of a relation more than than one time, that indicates that for that input in that location is more than i output. At any particular input value, at that place tin can be only one output if the relation is to be a role.

5.

When a horizontal line intersects the graph of a function more than in one case, that indicates that for that output at that place is more than ane input. A function is one-to-1 if each output corresponds to only one input.

27.

f ( iii ) = eleven ; f ( 3 ) = 11 ;
f ( two ) = 1 ; f ( 2 ) = 1 ;
f ( a ) = 2 a five ; f ( a ) = 2 a 5 ;
f ( a ) = 2 a + 5 ; f ( a ) = 2 a + 5 ;
f ( a + h ) = 2 a + ii h 5 f ( a + h ) = two a + 2 h 5

29.

f ( 3 ) = 5 + 5 ; f ( three ) = 5 + 5 ;
f ( 2 ) = 5 ; f ( 2 ) = five ;
f ( a ) = 2 + a + 5 ; f ( a ) = 2 + a + 5 ;
f ( a ) = 2 a 5 ; f ( a ) = 2 a 5 ;
f ( a + h ) = ii a h + 5 f ( a + h ) = ii a h + 5

31.

f ( iii ) = ii ; f ( iii ) = 2 ; f ( 2 ) = i 3 = ii ; f ( ii ) = i 3 = 2 ;
f ( a ) = | a ane | | a + i | ; f ( a ) = | a 1 | | a + i | ;
f ( a ) = | a 1 | + | a + 1 | ; f ( a ) = | a i | + | a + one | ;
f ( a + h ) = | a + h 1 | | a + h + 1 | f ( a + h ) = | a + h 1 | | a + h + i |

33.

g ( x ) g ( a ) x a = x + a + 2 , 10 a k ( ten ) grand ( a ) 10 a = x + a + 2 , 10 a

35.

a. f ( ii ) = 14 ; f ( 2 ) = fourteen ; b. ten = 3 x = 3

37.

a. f ( 5 ) = x ; f ( 5 ) = 10 ; b. 10 = i x = 1 or x = four x = 4

39.

  1. f ( t ) = half dozen 2 3 t ; f ( t ) = half-dozen two 3 t ;
  2. f ( three ) = eight ; f ( 3 ) = 8 ;
  3. t = 6 t = 6

53.

  1. f ( 0 ) = 1 ; f ( 0 ) = 1 ;
  2. f ( ten ) = 3 , x = 2 f ( x ) = 3 , x = ii or x = 2 x = ii

55.

not a function and so it is too not a 1-to-one office

59.

function, but not one-to-ane

67.

f ( x ) = one , 10 = 2 f ( x ) = 1 , ten = two

69.

f ( two ) = 14 ; f ( 1 ) = 11 ; f ( 0 ) = eight ; f ( one ) = 5 ; f ( 2 ) = 2 f ( two ) = 14 ; f ( one ) = 11 ; f ( 0 ) = eight ; f ( one ) = v ; f ( 2 ) = two

71.

f ( 2 ) = 4 ; f ( 1 ) = 4.414 ; f ( 0 ) = iv.732 ; f ( 1 ) = 5 ; f ( 2 ) = 5.236 f ( 2 ) = 4 ; f ( 1 ) = 4.414 ; f ( 0 ) = iv.732 ; f ( i ) = 5 ; f ( 2 ) = 5.236

73.

f ( ii ) = 1 9 ; f ( 1 ) = 1 3 ; f ( 0 ) = 1 ; f ( i ) = 3 ; f ( 2 ) = nine f ( 2 ) = one 9 ; f ( 1 ) = 1 3 ; f ( 0 ) = ane ; f ( 1 ) = 3 ; f ( 2 ) = nine

77.

[ 0 , 100 ] [ 0 , 100 ]

Graph of a parabola.

79.

[ 0.001 , 0 .001 ] [ 0.001 , 0 .001 ]

Graph of a parabola.

81.

[ i , 000 , 000 , 1,000,000 ] [ 1 , 000 , 000 , 1,000,000 ]

Graph of a cubic function.

83.

[ 0 , ten ] [ 0 , 10 ]

Graph of a square root function.

85.

[ −0.i , 0.1 ] [ −0.1 , 0.one ]

Graph of a square root function.

87.

[ 100 , 100 ] [ 100 , 100 ]

Graph of a cubic root function.

89.

  1. g ( 5000 ) = 50 ; 1000 ( 5000 ) = 50 ;
  2. The number of cubic yards of dirt required for a garden of 100 square feet is 1.

91.

  1. The top of a rocket higher up ground afterward 1 second is 200 ft.
  2. The height of a rocket above ground after 2 seconds is 350 ft.

3.2 Section Exercises

1.

The domain of a function depends upon what values of the independent variable make the function undefined or imaginary.

3.

There is no restriction on 10 ten for f ( x ) = 10 iii f ( x ) = x iii because you can accept the cube root of any real number. Then the domain is all real numbers, ( , ) . ( , ) . When dealing with the ready of existent numbers, you cannot take the foursquare root of negative numbers. And then x 10 -values are restricted for f ( x ) = ten f ( x ) = ten to nonnegative numbers and the domain is [ 0 , ) . [ 0 , ) .

v.

Graph each formula of the piecewise function over its corresponding domain. Apply the same scale for the ten x -axis and y y -axis for each graph. Indicate inclusive endpoints with a solid circle and exclusive endpoints with an open circumvolve. Apply an arrow to indicate or . . Combine the graphs to find the graph of the piecewise role.

15.

( , 1 ii ) ( 1 2 , ) ( , i 2 ) ( 1 2 , )

17.

( , 11 ) ( xi , 2 ) ( ii , ) ( , 11 ) ( 11 , 2 ) ( 2 , )

19.

( , iii ) ( three , 5 ) ( 5 , ) ( , 3 ) ( three , 5 ) ( 5 , )

25.

( , 9 ) ( 9 , ix ) ( 9 , ) ( , ix ) ( 9 , 9 ) ( 9 , )

27.

domain: ( 2 , viii ] , ( 2 , 8 ] , range [ six , 8 ) [ 6 , eight )

29.

domain: [ iv , 4], [ 4 , 4], range: [ 0 , two] [ 0 , 2]

31.

domain: [ 5 , three ) , [ 5 , 3 ) , range: [ 0 , 2 ] [ 0 , two ]

33.

domain: ( , 1 ] , ( , i ] , range: [ 0 , ) [ 0 , )

35.

domain: [ half dozen , i half dozen ] [ 1 6 , 6 ] ; [ 6 , 1 half dozen ] [ i 6 , 6 ] ; range: [ six , 1 half-dozen ] [ 1 6 , 6 ] [ 6 , 1 6 ] [ 1 6 , 6 ]

37.

domain: [ 3 , ) ; [ iii , ) ; range: [ 0 , ) [ 0 , )

39.

domain: ( , ) ( , )

Graph of f(x).

41.

domain: ( , ) ( , )

Graph of f(x).

43.

domain: ( , ) ( , )

Graph of f(x).

45.

domain: ( , ) ( , )

Graph of f(x).

47.

f ( 3 ) = 1 ; f ( ii ) = 0 ; f ( one ) = 0 ; f ( 0 ) = 0 f ( 3 ) = 1 ; f ( two ) = 0 ; f ( 1 ) = 0 ; f ( 0 ) = 0

49.

f ( 1 ) = iv ; f ( 0 ) = 6 ; f ( 2 ) = 20 ; f ( 4 ) = 34 f ( 1 ) = iv ; f ( 0 ) = vi ; f ( 2 ) = 20 ; f ( 4 ) = 34

51.

f ( one ) = 5 ; f ( 0 ) = three ; f ( two ) = 3 ; f ( 4 ) = 16 f ( 1 ) = 5 ; f ( 0 ) = iii ; f ( 2 ) = three ; f ( iv ) = 16

53.

domain: ( , ane ) ( 1 , ) ( , 1 ) ( one , )

55.

Graph of the equation from [-0.5, -0.1].

window: [ 0.5 , 0.i ] ; [ 0.5 , 0.1 ] ; range: [ 4 , 100 ] [ four , 100 ]

Graph of the equation from [0.1, 0.5].

window: [ 0.1 , 0.v ] ; [ 0.1 , 0.v ] ; range: [ iv , 100 ] [ 4 , 100 ]

59.

Many answers. 1 part is f ( x ) = i 10 two . f ( ten ) = 1 10 2 .

61.

  1. The fixed toll is $500.
  2. The cost of making 25 items is $750.
  3. The domain is [0, 100] and the range is [500, 1500].

3.3 Section Exercises

ane.

Yes, the average charge per unit of change of all linear functions is constant.

3.

The accented maximum and minimum chronicle to the entire graph, whereas the local extrema relate but to a specific region effectually an open up interval.

11.

1 13 ( 13 + h ) ane xiii ( 13 + h )

13.

three h 2 + nine h + ix three h two + ix h + ix

19.

increasing on ( , 2.5 ) ( 1 , ) , ( , 2.5 ) ( i , ) , decreasing on ( 2.five , 1 ) ( 2.5 , 1 )

21.

increasing on ( , 1 ) ( three , four ) , ( , 1 ) ( 3 , 4 ) , decreasing on ( 1 , 3 ) ( 4 , ) ( ane , three ) ( 4 , )

23.

local maximum: ( three , 60 ) , ( 3 , threescore ) , local minimum: ( iii , 60 ) ( 3 , 60 )

25.

absolute maximum at approximately ( seven , 150 ) , ( 7 , 150 ) , absolute minimum at approximately ( −7.five , −220 ) ( −seven.v , −220 )

35.

Local minimum at ( 3 , 22 ) , ( iii , 22 ) , decreasing on ( , 3 ) , ( , 3 ) , increasing on ( 3 , ) ( 3 , )

37.

Local minimum at ( 2 , 2 ) , ( 2 , two ) , decreasing on ( three , 2 ) , ( 3 , 2 ) , increasing on ( 2 , ) ( ii , )

39.

Local maximum at ( 0.5 , six ) , ( 0.5 , 6 ) , local minima at ( three.25 , 47 ) ( iii.25 , 47 ) and ( 2.1 , 32 ) , ( 2.one , 32 ) , decreasing on ( , three.25 ) ( , 3.25 ) and ( 0.5 , 2.1 ) , ( 0.v , 2.one ) , increasing on ( 3.25 , 0.5 ) ( 3.25 , 0.5 ) and ( 2.one , ) ( 2.1 , )

45.

ii.7 gallons per minute

47.

approximately –0.6 milligrams per day

three.iv Section Exercises

one.

Find the numbers that make the role in the denominator g thou equal to zero, and check for whatever other domain restrictions on f f and 1000 , g , such every bit an even-indexed root or zeros in the denominator.

3.

Yes. Sample answer: Allow f ( x ) = 10 + ane and thou ( x ) = x 1. f ( x ) = x + 1 and g ( ten ) = ten 1. And so f ( g ( ten ) ) = f ( x one ) = ( ten i ) + ane = 10 f ( thousand ( x ) ) = f ( x 1 ) = ( 10 1 ) + ane = x and g ( f ( x ) ) = thou ( x + 1 ) = ( x + 1 ) 1 = x . m ( f ( 10 ) ) = k ( x + 1 ) = ( x + 1 ) one = x . So f m = thou f . f g = g f .

5.

( f + thou ) ( x ) = two x + half-dozen , ( f + k ) ( x ) = 2 ten + 6 , domain: ( , ) ( , )

( f g ) ( x ) = 2 10 2 + 2 10 6 , ( f g ) ( ten ) = 2 ten 2 + 2 x half-dozen , domain: ( , ) ( , )

( f g ) ( 10 ) = ten 4 2 x 3 + six x 2 + 12 x , ( f one thousand ) ( x ) = x iv ii x three + vi x 2 + 12 x , domain: ( , ) ( , )

( f g ) ( x ) = ten 2 + ii x 6 x two , ( f chiliad ) ( x ) = x 2 + 2 ten half-dozen ten two , domain: ( , 6 ) ( 6 , vi ) ( vi , ) ( , 6 ) ( 6 , 6 ) ( six , )

vii.

( f + one thousand ) ( x ) = four x three + 8 x 2 + one two x , ( f + k ) ( 10 ) = 4 ten iii + 8 x 2 + 1 ii 10 , domain: ( , 0 ) ( 0 , ) ( , 0 ) ( 0 , )

( f g ) ( x ) = four x 3 + viii 10 2 one 2 x , ( f k ) ( x ) = 4 x 3 + 8 x 2 1 ii x , domain: ( , 0 ) ( 0 , ) ( , 0 ) ( 0 , )

( f g ) ( 10 ) = 10 + two , ( f g ) ( x ) = x + 2 , domain: ( , 0 ) ( 0 , ) ( , 0 ) ( 0 , )

( f thou ) ( x ) = 4 10 3 + 8 x ii , ( f thou ) ( 10 ) = iv ten 3 + 8 x 2 , domain: ( , 0 ) ( 0 , ) ( , 0 ) ( 0 , )

9.

( f + g ) ( x ) = 3 x 2 + x 5 , ( f + g ) ( x ) = 3 10 two + x five , domain: [ 5 , ) [ 5 , )

( f g ) ( ten ) = iii ten 2 ten 5 , ( f g ) ( x ) = iii ten 2 ten v , domain: [ 5 , ) [ v , )

( f yard ) ( x ) = 3 ten 2 10 5 , ( f one thousand ) ( x ) = 3 x 2 10 5 , domain: [ 5 , ) [ 5 , )

( f g ) ( 10 ) = 3 ten 2 10 5 , ( f grand ) ( x ) = 3 x 2 10 v , domain: ( 5 , ) ( 5 , )

xi.

  1. 3
  2. f ( g ( x ) ) = 2 ( 3 10 5 ) 2 + ane f ( g ( ten ) ) = ii ( 3 ten 5 ) two + i
  3. f ( g ( x ) ) = 6 x 2 2 f ( grand ( x ) ) = 6 x 2 two
  4. ( k g ) ( ten ) = 3 ( 3 ten 5 ) five = 9 x 20 ( chiliad g ) ( ten ) = 3 ( 3 10 5 ) five = 9 10 xx
  5. ( f f ) ( 2 ) = 163 ( f f ) ( 2 ) = 163

13.

f ( one thousand ( x ) ) = x 2 + 3 + ii , g ( f ( x ) ) = x + 4 ten + seven f ( k ( x ) ) = ten two + 3 + 2 , yard ( f ( x ) ) = x + four ten + 7

xv.

f ( thousand ( x ) ) = ten + ane x 3 3 = x + i 3 x , one thousand ( f ( x ) ) = x 3 + one x f ( m ( 10 ) ) = x + 1 x iii 3 = 10 + i 3 x , g ( f ( 10 ) ) = 10 3 + ane x

17.

( f g ) ( x ) = ane ii ten + 4 four = ten 2 , ( m f ) ( x ) = two ten 4 ( f g ) ( ten ) = 1 2 ten + four 4 = x 2 , ( yard f ) ( x ) = ii x 4

xix.

f ( chiliad ( h ( 10 ) ) ) = ( ane x + 3 ) 2 + i f ( k ( h ( x ) ) ) = ( 1 x + 3 ) 2 + 1

21.

  1. ( m f ) ( ten ) = 3 2 4 x ( yard f ) ( x ) = 3 2 4 ten
  2. ( , i 2 ) ( , 1 ii )

23.

  1. ( 0 , ii ) ( 2 , ) ; ( 0 , 2 ) ( 2 , ) ;
  2. ( , 2 ) ( 2 , ) ; ( , two ) ( two , ) ;
  3. ( 0 , ) ( 0 , )

27.

sample: f ( x ) = x iii yard ( 10 ) = x five f ( x ) = x 3 thousand ( x ) = x 5

29.

sample: f ( ten ) = 4 x g ( x ) = ( x + 2 ) two f ( 10 ) = four 10 thou ( 10 ) = ( x + 2 ) 2

31.

sample: f ( x ) = ten 3 g ( x ) = 1 ii x 3 f ( 10 ) = x iii one thousand ( x ) = 1 2 x 3

33.

sample: f ( ten ) = x iv g ( x ) = 3 10 2 x + 5 f ( x ) = x 4 1000 ( x ) = 3 x 2 ten + five

35.

sample: f ( x ) = 10 g ( x ) = 2 x + 6 f ( x ) = ten g ( 10 ) = 2 x + half-dozen

37.

sample: f ( x ) = 10 3 g ( x ) = ( x i ) f ( ten ) = x 3 g ( x ) = ( x 1 )

39.

sample: f ( x ) = ten 3 chiliad ( x ) = 1 x 2 f ( x ) = ten 3 g ( ten ) = 1 x 2

41.

sample: f ( ten ) = 10 thou ( x ) = 2 x 1 3 x + 4 f ( x ) = 10 g ( x ) = 2 10 1 3 x + 4

73.

f ( g ( 0 ) ) = 27 , g ( f ( 0 ) ) = 94 f ( g ( 0 ) ) = 27 , thou ( f ( 0 ) ) = 94

75.

f ( thousand ( 0 ) ) = 1 five , g ( f ( 0 ) ) = five f ( yard ( 0 ) ) = one 5 , yard ( f ( 0 ) ) = 5

77.

18 x two + 60 x + 51 18 x 2 + 60 x + 51

79.

g g ( x ) = 9 10 + 20 chiliad k ( ten ) = nine 10 + 20

87.

( f 1000 ) ( vi ) = six ( f chiliad ) ( 6 ) = vi ; ( g f ) ( 6 ) = vi ( g f ) ( 6 ) = 6

89.

( f g ) ( 11 ) = 11 , ( g f ) ( 11 ) = eleven ( f yard ) ( 11 ) = xi , ( g f ) ( eleven ) = 11

93.

A ( t ) = π ( 25 t + 2 ) 2 A ( t ) = π ( 25 t + ii ) ii and A ( 2 ) = π ( 25 4 ) 2 = 2500 π A ( two ) = π ( 25 4 ) 2 = 2500 π square inches

95.

A ( five ) = π ( ii ( 5 ) + 1 ) ii = 121 π A ( 5 ) = π ( 2 ( 5 ) + 1 ) 2 = 121 π foursquare units

97.

  1. N ( T ( t ) ) = 23 ( 5 t + 1.five ) 2 56 ( 5 t + i.5 ) + 1 N ( T ( t ) ) = 23 ( 5 t + 1.5 ) 2 56 ( five t + 1.5 ) + 1
  2. 3.38 hours

three.5 Section Exercises

1.

A horizontal shift results when a constant is added to or subtracted from the input. A vertical shifts results when a constant is added to or subtracted from the output.

three.

A horizontal compression results when a constant greater than 1 is multiplied by the input. A vertical compression results when a constant between 0 and 1 is multiplied by the output.

5.

For a part f , f , substitute ( x ) ( 10 ) for ( x ) ( x ) in f ( x ) . f ( 10 ) . Simplify. If the resulting office is the same as the original role, f ( ten ) = f ( x ) , f ( x ) = f ( 10 ) , then the function is even. If the resulting office is the opposite of the original part, f ( x ) = f ( x ) , f ( x ) = f ( 10 ) , then the original role is odd. If the role is not the same or the opposite, then the function is neither odd nor even.

7.

g ( 10 ) = | ten - 1 | iii g ( ten ) = | x - one | 3

9.

g ( x ) = 1 ( x + 4 ) 2 + two g ( x ) = 1 ( x + four ) 2 + 2

11.

The graph of f ( x + 43 ) f ( x + 43 ) is a horizontal shift to the left 43 units of the graph of f . f .

thirteen.

The graph of f ( x - 4 ) f ( x - 4 ) is a horizontal shift to the right iv units of the graph of f . f .

15.

The graph of f ( x ) + 8 f ( 10 ) + 8 is a vertical shift upwardly 8 units of the graph of f . f .

17.

The graph of f ( 10 ) 7 f ( 10 ) 7 is a vertical shift downwardly 7 units of the graph of f . f .

nineteen.

The graph of f ( x + iv ) one f ( x + 4 ) 1 is a horizontal shift to the left 4 units and a vertical shift down one unit of the graph of f . f .

21.

decreasing on ( , 3 ) ( , 3 ) and increasing on ( 3 , ) ( 3 , )

23.

decreasing on ( 0 , ) ( 0 , )

31.

chiliad ( ten ) = f ( x - i ) , h ( x ) = f ( 10 ) + i g ( x ) = f ( x - 1 ) , h ( x ) = f ( x ) + 1

33.

f ( x ) = | ten - iii | 2 f ( x ) = | ten - 3 | 2

35.

f ( x ) = x + 3 ane f ( x ) = x + three i

37.

f ( x ) = ( ten - 2 ) 2 f ( ten ) = ( x - 2 ) 2

39.

f ( x ) = | x + 3 | 2 f ( x ) = | x + iii | two

43.

f ( x ) = ( x + 1 ) ii + two f ( x ) = ( ten + 1 ) 2 + 2

45.

f ( x ) = x + 1 f ( x ) = x + ane

53.

The graph of grand g is a vertical reflection (beyond the x x -centrality) of the graph of f . f .

55.

The graph of m g is a vertical stretch by a factor of 4 of the graph of f . f .

57.

The graph of 1000 1000 is a horizontal compression past a factor of 1 5 1 5 of the graph of f . f .

59.

The graph of g 1000 is a horizontal stretch by a factor of 3 of the graph of f . f .

61.

The graph of grand k is a horizontal reflection beyond the y y -axis and a vertical stretch past a factor of iii of the graph of f . f .

63.

g ( x ) = | iv x | m ( x ) = | 4 x |

65.

g ( x ) = 1 iii ( x + ii ) ii three yard ( 10 ) = 1 three ( x + 2 ) 2 3

67.

g ( x ) = one two ( 10 - 5 ) ii + 1 g ( x ) = 1 two ( x - 5 ) 2 + ane

69.

The graph of the office f ( x ) = x 2 f ( x ) = ten 2 is shifted to the left 1 unit, stretched vertically past a factor of iv, and shifted downwardly v units.

Graph of a parabola.

71.

The graph of f ( x ) = | 10 | f ( 10 ) = | x | is stretched vertically by a factor of 2, shifted horizontally 4 units to the right, reflected across the horizontal axis, and then shifted vertically 3 units up.

Graph of an absolute function.

73.

The graph of the function f ( 10 ) = ten 3 f ( 10 ) = x iii is compressed vertically past a factor of one two . one 2 .

Graph of a cubic function.

75.

The graph of the function is stretched horizontally by a cistron of 3 and then shifted vertically downward past iii units.

Graph of a cubic function.

77.

The graph of f ( 10 ) = 10 f ( x ) = x is shifted right 4 units and then reflected across the vertical line x = four. x = 4.

Graph of a square root function.

three.6 Section Exercises

1.

Isolate the accented value term then that the equation is of the form | A | = B . | A | = B . Class one equation by setting the expression inside the absolute value symbol, A , A , equal to the expression on the other side of the equation, B . B . Form a second equation by setting A A equal to the contrary of the expression on the other side of the equation, B . B . Solve each equation for the variable.

iii.

The graph of the accented value office does not cantankerous the 10 x -axis, so the graph is either completely higher up or completely beneath the 10 x -axis.

5.

The distance from x to 8 can be represented using the absolute value statement: ∣ x − 8 ∣ = 4.

nine.

There are no x-intercepts.

13.

( 0 , 4 ) , ( four , 0 ) , ( two , 0 ) ( 0 , 4 ) , ( 4 , 0 ) , ( 2 , 0 )

15.

( 0 , 7 ) , ( 25 , 0 ) , ( 7 , 0 ) ( 0 , 7 ) , ( 25 , 0 ) , ( 7 , 0 )

33.

range: [ 400 , 100 ] [ 400 , 100 ]

Graph of an absolute function.

37.

There is no solution for a a that will keep the function from having a y y -intercept. The absolute value function e'er crosses the y y -intercept when 10 = 0. x = 0.

39.

| p 0.08 | 0.015 | p 0.08 | 0.015

41.

| x 5.0 | 0.01 | x v.0 | 0.01

three.7 Section Exercises

1.

Each output of a function must have exactly one output for the function to be one-to-one. If any horizontal line crosses the graph of a function more than than once, that means that y y -values repeat and the function is not one-to-i. If no horizontal line crosses the graph of the function more than than once, so no y y -values repeat and the function is ane-to-i.

3.

Yes. For example, f ( x ) = 1 x f ( 10 ) = 1 x is its ain inverse.

v.

Given a function y = f ( ten ) , y = f ( ten ) , solve for x ten in terms of y . y . Interchange the ten 10 and y . y . Solve the new equation for y . y . The expression for y y is the changed, y = f 1 ( 10 ) . y = f one ( x ) .

7.

f one ( x ) = x 3 f 1 ( x ) = ten 3

nine.

f 1 ( 10 ) = 2 x f i ( x ) = 2 x

eleven.

f 1 ( x ) = ii 10 x 1 f one ( x ) = ii x ten i

13.

domain of f ( x ) : [ 7 , ) ; f 1 ( x ) = x 7 f ( x ) : [ 7 , ) ; f i ( x ) = x 7

15.

domain of f ( x ) : [ 0 , ) ; f 1 ( ten ) = x + 5 f ( x ) : [ 0 , ) ; f one ( ten ) = 10 + 5

xvi.

a. f ( g ( ten ) ) = x f ( 1000 ( x ) ) = 10 and grand ( f ( 10 ) ) = ten . thousand ( f ( x ) ) = x . b. This tells united states of america that f f and g yard are inverse functions

17.

f ( thou ( x ) ) = 10 , chiliad ( f ( x ) ) = x f ( g ( x ) ) = 10 , one thousand ( f ( x ) ) = x

41.

x x 1 4 7 12 xvi
f 1 ( x ) f 1 ( x ) 3 six 9 13 14

43.

f 1 ( ten ) = ( 1 + x ) 1 / 3 f 1 ( x ) = ( 1 + ten ) 1 / iii

Graph of a cubic function and its inverse.

45.

f 1 ( x ) = five ix ( x 32 ) . f one ( x ) = 5 9 ( x 32 ) . Given the Fahrenheit temperature, x , ten , this formula allows you to calculate the Celsius temperature.

47.

t ( d ) = d 50 , t ( d ) = d 50 , t ( 180 ) = 180 50 . t ( 180 ) = 180 l . The time for the car to travel 180 miles is iii.six hours.

Review Exercises

five.

f ( iii ) = 27 ; f ( 3 ) = 27 ; f ( 2 ) = ii ; f ( 2 ) = 2 ; f ( a ) = ii a ii iii a ; f ( a ) = two a 2 3 a ;
f ( a ) = 2 a two 3 a ; f ( a ) = two a 2 3 a ; f ( a + h ) = ii a 2 + 3 a 4 a h + 3 h 2 h two f ( a + h ) = 2 a 2 + 3 a 4 a h + 3 h 2 h 2

17.

x = 1.8 x = 1.8 or or x = 1.viii or ten = 1.8

nineteen.

64 + lxxx a 16 a 2 1 + a = 16 a + 64 64 + 80 a sixteen a 2 1 + a = 16 a + 64

21.

( , 2 ) ( 2 , half-dozen ) ( half dozen , ) ( , 2 ) ( two , 6 ) ( half-dozen , )

27.

increasing ( 2 , ) ; ( ii , ) ; decreasing ( , 2 ) ( , 2 )

29.

increasing ( 3 , 1 ) ; ( 3 , ane ) ; constant ( , three ) ( one , ) ( , 3 ) ( 1 , )

31.

local minimum ( 2 , 3 ) ; ( 2 , three ) ; local maximum ( 1 , 3 ) ( 1 , 3 )

33.

( 1.viii , 10 ) ( 1.8 , ten )

35.

( f m ) ( x ) = 17 18 x ; ( g f ) ( 10 ) = 7 eighteen x ( f grand ) ( ten ) = 17 18 x ; ( g f ) ( x ) = 7 18 10

37.

( f g ) ( ten ) = 1 ten + 2 ; ( g f ) ( x ) = 1 x + ii ( f one thousand ) ( x ) = 1 x + 2 ; ( g f ) ( ten ) = 1 10 + 2

39.

( f g ) ( x ) = 1 + x 1 + 4 x , ten 0 , x 1 4 ( f thou ) ( x ) = 1 + ten 1 + 4 x , x 0 , x 1 4

41.

( f g ) ( 10 ) = 1 x , x > 0 ( f yard ) ( 10 ) = 1 x , x > 0

43.

sample: g ( 10 ) = 2 x one 3 x + 4 ; f ( x ) = x 1000 ( x ) = 2 x 1 3 x + four ; f ( x ) = x

55.

f ( ten ) = | x 3 | f ( x ) = | x 3 |

63.

f ( x ) = 1 2 | x + 2 | + 1 f ( x ) = i 2 | x + 2 | + 1

65.

f ( x ) = three | x 3 | + 3 f ( 10 ) = 3 | x three | + 3

69.

f i ( x ) = x - 9 10 f 1 ( x ) = x - 9 10

71.

f 1 ( x ) = x - 1 f one ( x ) = x - 1

73.

The function is one-to-i.

Practice Examination

1.

The relation is a function.

v.

The graph is a parabola and the graph fails the horizontal line test.

xix.

f ane ( x ) = x + 5 3 f i ( x ) = x + 5 3

21.

( , 1.1 ) and ( i.i , ) ( , 1.i ) and ( ane.1 , )

23.

( one.ane , 0.9 ) ( i.i , 0.9 )

27.

f ( 10 ) = { | x | if x 2 3 if x > two f ( x ) = { | x | if ten 2 3 if x > ii

33.

f ane ( x ) = x 11 2 f i ( x ) = x 11 2

Cc Algebra Chapter 3 Answers,

Source: https://openstax.org/books/college-algebra/pages/chapter-3

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